7x^2-26X+19=0

Solution for 7x^2-26X+19=0 equation:

7x^2-26x+19=0

a = 7; b = -26; c = +19;
Δ = b2-4ac
Δ = -262-4·7·19
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-12}{2*7}=\frac{14}{14}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+12}{2*7}=\frac{38}{14}
=2+5/7
$